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8n^2+57n+7=0
a = 8; b = 57; c = +7;
Δ = b2-4ac
Δ = 572-4·8·7
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-55}{2*8}=\frac{-112}{16} =-7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+55}{2*8}=\frac{-2}{16} =-1/8 $
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